Подскажите как скомпилировать эту программу в ОС Windows vista.
#include <stdio.h> #include <math.h> #include "mpi.h" double f(double a) { return (4.0 / (1.0+ a*a)); } int main(int argc, char **argv) { int done = 0, n, myid, numprocs, i; double PI25DT = 3.141592653589793238462643; double mypi, pi, h, sum, x; double startwtime = 0.0, endwtime; int namelen; char processor_name[MPI_MAX_PROCESSOR_NAME]; MPI_Init(&argc, &argv); MPI_Comm_size(MPI_COMM_WORLD,&numprocs); MPI_Comm_rank(MPI_COMM_WORLD,&myid); MPI_Get_processor_name(processor_name,&namelen); fprintf(stdout, "Process %d of %d is on %s\n", myid,numprocs,processor_name); fflush(stdout); while(!done) { if(myid==0) { fprintf(stdout, "Enter the number of intervals: (0 quits) "); fflush(stdout); if(scanf("%d",&n) != 1) { fprintf(stdout, "No number entered; quitting\n"); n = 0; } startwtime = MPI_Wtime(); } MPI_Bcast(&n, 1, MPI_INT, 0, MPI_COMM_WORLD); if(n==0) done = 1; else { h = 1.0 / (double) n; sum = 0.0; // Обсчитывание точки, закрепленной за процессом for(i = myid + 1 ; (i <= n) ; i += numprocs) { x = h * ((double)i - 0.5); sum += f(x); } mypi = h * sum; MPI_Reduce(&mypi, &pi, 1, MPI_DOUBLE, MPI_SUM, 0, MPI_COMM_WORLD);
if(myid==0) { printf("PI is approximately %.16f, Error is %.16f\n", pi, fabs(pi - PI25DT)); endwtime = MPI_Wtime(); printf("wall clock time = %f\n", endwtime-startwtime); fflush(stdout); } } } MPI_Finalize(); return 0; }
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